The combustion equation for 2-pentene is C5H10 + 7.5O2 -> 5CO2 + 5H2O. This equation shows that 2-pentene reacts with oxygen to produce carbon dioxide and water. The balanced equation indicates that for every one molecule of 2-pentene, 7.5 molecules of oxygen are required for complete combustion. **

Yes, the task is about the polymerization of pentene. Pentene is a type of alkene, which can undergo polymerization to form a polymer chain. This process involves the repeated addition of pentene monomer units to form a long chain polymer. The polymerization of pentene is an important industrial process for the production of various polyethylene materials. **

Trans-2-pentene can have both CH3 substituents below on the same side because the trans configuration refers to the orientation of the two highest priority groups on the double bond, which in this case are the two CH3 groups. In trans-2-pentene, the two CH3 groups are on opposite sides of the double bond, with the other substituents (H atoms) also on opposite sides. This results in a trans configuration, even though the CH3 groups are both below on the same side. **

Even though the CH3 substituents are both pointing downwards on the same side, the molecule can still be trans-2-pentene. In trans-2-pentene, the double bond is between the second and third carbon atoms, and the CH3 groups are on the same side of the double bond. This arrangement results in a trans configuration, where the two CH3 groups are on opposite sides of the double bond, even though they are both pointing downwards. **

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